In complex number ( especially for any real number) x and integer n it holds that
(cos(x) + i(sinx))^n = cos(nx) + isin(nx) where i is the imaginary unit representing as i*i = -1.
This is called De Moivre's theorem.
This theorem can be proved by Euler's theorem which states
e^(i*x) = cos(x) + isin(x)
then
(e^(i*x))^n = (cos(x) + isin(x))^n which equals to
e^(ixn) = cos(nx) + isin(nx)
resulting to
(cos(x) + isin(x))^n = cos(nx) + isin(nx)
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