Use the chain rule to differentiate y=(x-3)^(-3)

Hint: the chain rule states that for y=u(x) ^a, the derivative will be dy/dx = dy/du * du/dxSo we just need to find dy/du and du/dx!In this case u(x)=x-3, so du/dx = 1.from y=u^(-3), dy/du = -3u^(-4).This means we know dy/dx = -3u^(-4) * 1Converting from u to x, we get dy/dx = -3 (x-3)^(-4) .... done! 

Answered by Rosemary T. Maths tutor

4682 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

find dy/dx= x^2 +x^3


A curve with equation y=f(x) passes through point P at (4,8). Given that f'(x)=9x^(1/2)/4+5/2x^(1/2)-4 find f(X).


Shower-cleaner liquid is sold in spray bottles. The volume of liquid in a bottle may be modelled by a normal distribution with mean 955 ml and a standard deviation of 5 ml. Determine the probability that the volume in a particular bottle is:


Integrate (x)(e^x) with respect to x and then integrate (x)(e^x) with respect to y.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences