The integral of log(x) is not necessarily straight-forward. Though we can use the fact that d/dx(log(x)) = 1/x to help us.
Rather than simply trying to integrate log(x), we can use integration by parts on 1 x log(x) (as in 'one times' log(x)).
So we can differentiate the log(x) part and integrate the 1 part to give:
xlog(x) - ∫ 1 dx = xlog(x) - x
Note: if the middle step isn't clear, we can write it more explicitly as
u = log(x) v' = 1
u' = 1/x v = x
Where the rule for integration by parts is written as:
uv' = uv - ∫ u'v , where u and v are functions of x