Solve simultaneously: x + y + 3 = 0 and y = 2x^2 +3x - 1

First Step:

I believe here it is important to firstly look at each equation on its own and just try to think how the examiner would want you to answer this type of question.

Second Step:

Recognise that both equations have an individual y in them therefore we can use this connection to solve the equation through substitution.

By Substitution we get:

x + 2x^2 + 3x - 1 + 3 = 0

which then simplies to:

2x^2 + 4x + 2  

and then divide everything by 2 gets you:

x^2 + 2x +1 = 0 

Answer:

(x+1)^2 = 0  

x = -1 (repeated root) and y = -2

JS
Answered by Jamie S. Maths tutor

4875 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you integrate ln(x)?


Solve the equation 8x^6 + 7x^3 -1 = 0


Show that 2sin(2x)-3cos(2x)-3sin(x)+3=sin(x)(4cos(x)+6sin(x)-3)


Find the equation of the line perpendicular to the line y= 3x + 5 that passes through the point (-1,4)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning