Solve simultaneously: x + y + 3 = 0 and y = 2x^2 +3x - 1

First Step:

I believe here it is important to firstly look at each equation on its own and just try to think how the examiner would want you to answer this type of question.

Second Step:

Recognise that both equations have an individual y in them therefore we can use this connection to solve the equation through substitution.

By Substitution we get:

x + 2x^2 + 3x - 1 + 3 = 0

which then simplies to:

2x^2 + 4x + 2  

and then divide everything by 2 gets you:

x^2 + 2x +1 = 0 

Answer:

(x+1)^2 = 0  

x = -1 (repeated root) and y = -2

JS
Answered by Jamie S. Maths tutor

4761 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The velocity of a moving body is given by an equation v = 30 - 6t, where v - velocity in m/s, t - time in s. A) What is the acceleration a in m/s^2? B) Find the expression for the displacement s in terms of t given the initial displacement s(0)=10 m.


By first expanding the brackets, differentiate the equation: y=(4x^4 + 3x)(2x^2 - 9)


Prove: (1-cos(2A))/sin(2A) = tan(A)


Find the gradient of the exponential curve y(x)=(9e^(7x))/(12e^(2x)) at x=2/5


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning