Solve simultaneously: x + y + 3 = 0 and y = 2x^2 +3x - 1

First Step:

I believe here it is important to firstly look at each equation on its own and just try to think how the examiner would want you to answer this type of question.

Second Step:

Recognise that both equations have an individual y in them therefore we can use this connection to solve the equation through substitution.

By Substitution we get:

x + 2x^2 + 3x - 1 + 3 = 0

which then simplies to:

2x^2 + 4x + 2  

and then divide everything by 2 gets you:

x^2 + 2x +1 = 0 

Answer:

(x+1)^2 = 0  

x = -1 (repeated root) and y = -2

Answered by Jamie S. Maths tutor

4327 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Solve for 0<=θ<π, the equation sin3θ-(sqrt3)cosθ=0 (C2)


Differentiate y=e^(x^2+2x)


Find the equation of the normal to the curve y=2x^3 at the point on the curve where x=2. Write in the form of ax+by=c.


What is the difference between a scalar and vector quantity?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences