How much work must be done on a 4.0kg frictionless trolley, to accelerate it from rest to a velocity of 5.0m/s?

It must firstly be noted that, in general, the work done on an object is equal to its gain in energy.The trolley has gained kinetic energy. This can be calculated using the formula: "KE = (1/2)mv^2" where 'm' is the mass of the object and 'v' is its new velocity, when accelerating from rest.The KE gained by the trolley = (1/2) m v^2                              = (1/2) x 4 x 5^2                              = 50 JSo the work done on the trolley is equal to 50J.

Answered by Will W. Physics tutor

2798 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Why does a change in depth in water give a far greater difference in pressure than the same change in height in air?


Help! How do I rearrange equations?


In the photoelectric effect, why is the kinetic energy of the electrons independent of the intensity of light?


Describe the motion of a moving object with a given Displacement-Time graph. For each section on the graph, indicate the direction of motion and identify if the object is accelerating or not. What would the object's Velocity-Time graph look like?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences