How much work must be done on a 4.0kg frictionless trolley, to accelerate it from rest to a velocity of 5.0m/s?

It must firstly be noted that, in general, the work done on an object is equal to its gain in energy.The trolley has gained kinetic energy. This can be calculated using the formula: "KE = (1/2)mv^2" where 'm' is the mass of the object and 'v' is its new velocity, when accelerating from rest.The KE gained by the trolley = (1/2) m v^2                              = (1/2) x 4 x 5^2                              = 50 JSo the work done on the trolley is equal to 50J.

Answered by Will W. Physics tutor

2828 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

What is the difference between speed and velocity?


What is meant by 'resolving a vector into its components'?


Which renewable energy methods are the best?


When a force is applied to a spring, the spring extends by 12cm. The spring has a spring constant of 25 N/m. Calculate the force applied to the string in N.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences