The triangle ABC is such that AC=8cm, CB=12cm, angle ACB=x radians. The area of triangle ABC = 20cm^2. Show that x=0.430 (3sf)
From the equation of the area of a triangle,
Area = 1/2 ACCBsin(C)
20 = 1/2 * 8 *12 * sin(x)
=> sin(x) = 0.416666...
=> x = 0.430 to 3sf
LD
Related Maths A Level answers
All answers ▸Show the sum from n=0 to 200 of x^n given that x is not 1, is (1-x^201)/(1-x) hence find the sum of 1+2(1/2)+3(1/2)^2+...+200(1/2)^199
Differentiate the function y=(6x-1)^7
The curve C has the equation y=3x/(9+x^2 ) (a) Find the turning points of the curve C (b) Using the fact that (d^2 y)/(dx^2 )=(6x(x^2-27))/(x^2+9)^3 or otherwise, classify the nature of each turning point of C
Express the following in partial fractions: (x^2+4x+10)/(x+3)(x+4)(x+5)