N = 2A + B. A is a two-digit square number. B is a two-digit cube number. What is the smallest possible value of N?

A is a 2-digit square number. In order to find the smallest N number we want to find the smallest possible 2-digit sqaure number. To sqaure a number means to multiply this number by itself, e.g. the square number of 2 is 4 as 2x2=4. Instead of writing 2x2 we write 22. Hence, 1 squared equals 1 (12=1); 22=4; 32=9; 42=16, therefore the smallest square number is 16, so A=16

B is a 2-digit cube number. Again, in order to find the smallest N number we want to find the smallest possible 2 -digit cube number. To find the cube number, we multiply a given number by itself 3 times, e.g. the cube bumber of 2 is 8 as 2x2x2=8. If we follow the same logic, 1 cubed equals 1 (13=1); 23=8; 33=27, therefore the smallest cubed number is 27, so B=27.

N=2A + B; if we substitue A with 16 and B with 27, we get N=2x16 + 27, therefore N=59

Answered by Silvia K. Maths tutor

6682 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations 7x - 2y = 22 and 5x + 3y = 29


A metal sphere of radius 15cm is melted down and recast into a solid cylinder of radius 6cm. Calculate the height of the cylinder.


An isosceles triangle has a base with length x+4 and the other two sides have length x+3. The perimeter of this isosceles triangle is 16cm. Find the area of the triangle.


solve the simultaneous equations: 2x-3y = 16 and x + 2y = - 6


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences