Solve the following simultaneous equations: 4x + y = 14 and 6x - y = 16

First, write out the equations beneath each other:

4x + y = 14

6x - y = 16

 

Then, label the equations a and b (let's take the top one as a, and the bottom one as b)

We always look to eliminate either the x term, or the y term

Equation b + equation a would elimate the y term. i.e. -y = -1y; so, -1+1=0

Now, add the two equations together:

10x=30

Then, simplify to find out the value of a single x

x = (30/10); x = 3

 

Then, we substitute our x value into either of the equations, to work out y. 

Let's do it with equation a:

4(3) + y = 14

12 + y = 14; y= 14-12; y=2

 

We can check by putting both the x and y values into equation b to check it works:

6(3) - 2 = 16

18-2= 16

It works!!

Answered by Rebecca S. Maths tutor

6570 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Express 5/8 as a decimal


If Angela gets 50p change from a £2 coin, how much is 250g of butter? (full details below)


ABC is a triangle with sides of length AB, 12m and BC,14m. Angle ACB = 43 degrees. Find the area of the triangle.


What is completing the square and how do I do it?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences