What is [(x+1)/(3x^(2)-3)] - [1/(3x+1)] in its simplest form?

First simplify the expression; 3x^(2)-3 to get;

[(x+1)/3(x^(2)-1)] - [1/(3x+1)] 

Using the fact that x^(2)-1 is the difference of two squares, we can simplify it to;

[(x+1)/3(x+1)(x-1)] - [1/(3x+1)] 

which simplifies to;

[1/3(x-1)] - [1/(3x+1)] 

finally adding the two gives

 4/3(x-1)(3x+1) 

Answered by Francis Odhiambo O. Maths tutor

9486 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

(A) express 4^x in terms of y given that 2^x = y. (B) solve 8(4^x ) – 9(2^x ) + 1 = 0


Differentiate f(x) with respect to x. Find the stationary value and state if it is a maxima, minima or point of inflection f(x) = 6x^3 + 2x^2 + 1


The curve C is defined by x^3 – (4x^2 )y = 2y^3 – 3x – 2. Find the value of dy/dx at the point (3, 1).


How do you differentiate a function containing e?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences