Differentiate y = x^3 +x^2 - 4x +5 with respects to x.

When differentiating, you want to use the formula ax^n differentiates to (an)x^(n-1), so for the example above, x^3 where a is 1, and n is 3, the differentiation is (13)x^(3-1) which results to 3x^2.

This is repeated for x^2 as 2x. For -4x, a = -4 and n = 1 so differentiating this becomes (-41)x^(1-1)  which results to -4 as x^0 is 1. When the term does not have an x term like for instance +5, the term can be disregarded. It can be rewritten as 5x^0 and when differentiated, becomes (50)x^0-1. This results in the answer being 0.

The overall answer for this question is dy/dx = 3x^2 + 2x - 4.   

MS
Answered by Manojhan S. Maths tutor

4381 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Integrate 3 sin(x) + cos(2x)


Integrate cos^2x + cosx + sin^2x + 3 with respect to x


How do I differentiate 4x^3 + 2x + x^4 with respect to x?


I struggle with integration, and don't understand why we need to do it


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning