Differentiate y = x^3 +x^2 - 4x +5 with respects to x.

When differentiating, you want to use the formula ax^n differentiates to (an)x^(n-1), so for the example above, x^3 where a is 1, and n is 3, the differentiation is (13)x^(3-1) which results to 3x^2.

This is repeated for x^2 as 2x. For -4x, a = -4 and n = 1 so differentiating this becomes (-41)x^(1-1)  which results to -4 as x^0 is 1. When the term does not have an x term like for instance +5, the term can be disregarded. It can be rewritten as 5x^0 and when differentiated, becomes (50)x^0-1. This results in the answer being 0.

The overall answer for this question is dy/dx = 3x^2 + 2x - 4.   

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Answered by Manojhan S. Maths tutor

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