Solve for 0<=θ<π, the equation sin3θ-(sqrt3)cosθ=0 (C2)

Rearrange the equation to give sin3θ=(sqrt3)cos3θ, then divide through by cos3θ to give sin3θ/cos3θ=sqrt3. We know from our trig identities that sinx/cosx=tanx, so our equation now becomes tan3θ=sqrt3. Use your calculator to find 3θ, I got 3θ=π/3, so θ=π/9 which is within our range for θ.

Answered by Becky H. Maths tutor

8083 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Surds question 3 - C1 2016 Edexcel


If the velocity of a particle is given by t^2+t, then determine the acceleration of the particle when t=4.


differentiate y = (4-x)^2


Integral between 0 and pi/2 of cos(x)sin^2(x)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences