Solve the simultaneous equations; 5x + 2y = 11, 4x – 3y = 18

Here you have 2 equations and you need to find the value of x and of y. First we are going to find the value of x. We do this by eliminating the y factor by multiplying and adding the equations. If we multiply EQUATION 1 by 3 and EQUATION 2 by 2, the equations look like; 15x+6y=33, 8x-6y=36. Hence have equal y factors. Adding the equations together we eliminate the y values and have 1 equation that is 23x=69, so x=3. Subbing x=3 into either equations we can find the value of y.

  1. 5x+2y=11, 5*3+2y=11, 15+2y=11, 2y=-4, y=-2

OR

2.4x-3y=18, 4*3-3y=18, 12-3y=18, -3y=6, y=-2

AC
Answered by Alice C. Maths tutor

19749 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve 2x+y=6, 3x+2y=3 for x and y.


The perimeter of a right-angled triangle is 78 cm. The lengths of its sides are in the ratio 3: 4 : 6 Work out the area of the triangle.


5 tins of soup have a total weight of 1750 grams. 4 tins of soup and 3 packets of soup have a total weight of 1490 grams. Work out the total weight of 3 tins of soup and 2 packets of soup.


Peter is 180cm tall, correct to 2 significant figures. Alice is 150cm tall, correct to 2 significant figures. What is the upper and lower bound of the difference in their heights?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning