Solve equation 1/x + x^3 + 5x=0

For x!=0, multiply the equation by x to get x^4+5x^2+1=0. Then substitute t=x^2 where t>=0. So the equation has a form t^2+5t+1. Then find the discriminant and two roots. One of the roots t2<0 doesn't meet the condition for t>=0 so we take t1=x^2, then we find two x roots, and have a final solution.

Answered by Jakub O. Maths tutor

3695 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Why is (x^3 - 7x^2 +13x - 6) divisible with (x-2)?


(Core 2) Show that the region bounded by the curve y = 7x+ 6 - (1/x^2), the x axis and the lines x = 1 and x = 2 equals 16


If f(x)=7xe^x, find f'(x)


What is calculus?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences