y=6x-2
x2-4x+19
Both equations are equal to Y, hence can be substituted into each other;
6x-2= x^2-4x+19
Now we only have X terms in our equations
Bring all the like X terms together, and make equation equal to 0
Now we have a simultaneous equations which we can factorise
0=(x-7)(x-3)
We can now solve this as either x-7 must equal 0 or x-3 must equal 0
0=x-7………………………………x=7
Or
0=x-3………………………………x=3
Hence answer is x=7 or 3