Using the quadratic equation, solve 3x^2+2x-15 to two decimal places.

The quadratic equation is x=(-b+-SQRT(b^2-4ac))/2a. In this instance, a = 3, b = 2, and c = 15. Simply putting the numbers in place of the letter counterpart, gives an answer of 1.93 and -2.59 to two decimal places.

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Matt has 3 piles of coins, A , B and C. Altogether there was 72p. Pile B had twice as much as pile A. Pile C had three times as much as pile B. How much money was in Pile C?


Factorise fully 3a^3b + 12a^2b^2 + 9a^5b^3


How would I simplify this? (x-2)(x+3)


Please expand the brackets in the following equation to get a quadratic equation. Then, please show using the quadratic formula that the solutions to the equation are x=3 and x=5. Here is the starting equation: (x-3)(x-5)=0


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