x=1, y=3; Firstly, rearranging for x in the first equation: x = (7-2y); Substitute this into the second equation: 3y - (7 -2y) = 8; Expand: 3y -7 +2y = 8 (watch negative) 3y +2y = 15 Therefore, 5y = 15 and y=3. Now substitute Y into either of the equations to find x: 2(3) + x = 7 6 + x = 7 Therefore x = 1.