Rearrange y = (3x+5)/x to make x the subject

Step 1: Multiply both sides by x to obtain xy = 3x + 5. Step 2: Place all the 'x' terms on the same side of the equation to obtain xy-3x=5 Step 3: Factor out x from the left side of the equation: x (y-3) = 5. Step 4: Now you can single out x by dividing both sides of the equation by (y-3) so that x = 5/(y-3)

AS
Answered by Araba S. Maths tutor

26245 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I solve the following simultaneous equations? y = 2x -3 and 2x + 3y = 23


The line L passes through the points (-2,3) and (6,9). How do I find the equation of the line that is parallel to L and passes through the point (5,-1)?


Solve algebraically 6a + b = 16 and 5a - 2b = 19


Solve 56x + 10 = 60 - 48x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning