Find the roots of 2x^2-5x-6=0 to 3dps

if we see the phrase "to N dps" this is a big hint to use the quadratic formula. The first thing we have to do is to is pick out the co-efficients ax^2+bx+c=0 a=2, b=-5, c=-6 Now we can pug these numbers into the quadratic formula x=(-b±√(b^2-4ac))/2a x=(5±√(25-42-6))/4 x=(5±√(25+48))/4 x=(5±√73)/4 x=3.386,-0.886 (3dps)

Answered by Liam M. Maths tutor

4150 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The population of a town in 2014 was 80058. This was a 65% increase on its population in 1994. What was the population in 1994?


Solve the simultaneous equations: 2x + y = 18, x - y =6.


How do you know whether to use sin, cos or tan to find the angle in a triangle?


Solve: 5x - 2 > 3x + 11


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences