Integrate the following equation to find y: dy/dx = 3x^2 + 2x + 6

Notice that integration is simply the opposite of differentiation. So, if we just integrate this term-by-term then we can find an expression of y in terms of x.

So, when we integrate dy/dx becomes y.

Integrating 3x^2, we add 1 to the power and divide the coefficient by this new power. So we will get 3x^3/3 which is the same as x^3.

Then, by the same process, integrating 2x will give 2x^2/2 which is equal to x^2.

Now, if we think of 6 as the same as 6x^0 (since anything ^0 equals 1) then by the same process we get 6x^1/1 which is just 6x.

Finally, we must remember that we cannot find any term which are just a constant as they would have disappeared when y was differentiated, so we must add a +c to the end.

Bringing this all together, we get y=x^3+x^2+6x+c

MM

Related Maths A Level answers

All answers ▸

Solve the inequality x^2 – 5x – 14 > 0.


Integrate 1 / x(2sqrt(x)-1) on [1,9] using x = u^2 (u > 0).


The line L has equation y = 5 - 2x. (a) Show that the point P (3, -1) lies on L. (b) Find an equation of the line perpendicular to L that passes through P.


Show that the equation 2sin^2(x) + 3sin(x) = 2cos(2x) + 3 can be written as 6sin^2(x)+3sin(x) - 5 = 0. Hence solve for 0 < x < 360 degrees. Giving your answers to 1.d.p.