(2x + 3)/(x-4) - (2x - 8)/(2x + 1) = 1

Multiply through by both denominators, giving us the equation (2x + 3)(2x + 1) - (2x - 8)(x - 4) = (x-4)(2x +1). If we expand the brackets, we arrive at 4x^2 + 8x + 3 - (2x^2 -16x + 32) = 2x^2 -7x -4. If we simply we now have 2x^2 + 24x - 29 = 2x^2 - 7x -4. At this stage we can spot we can remove 2x^2 from both sides and rearrange so that we have all the x terms on one side and all the numbers on the other. We do this by adding 7x and 29 to both sides. This gives us 31x = 25, dividing through by 31 gives us x = 25/31, which is the solution.

Answered by Harry R. Maths tutor

3190 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Two points P(–4, –1) and Q(–8, 5) are joined by a straight line. Work out the coordinates of the midpoint of the line PQ.


how do you factorise a quadratic where there is a number in front of the x squared?


How do I expand (x-2)(3x+3) into a quadratic?


Show that 0.81 reocurring = 9/11


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences