Find the integral of xcosx(dx)

Firstly, let's split the equation "xcosx" into two parts to integrate them separately. 1) Let u=x and dv/dx=cosx 2)As the integral of x is 1, du/dx=1 3)To find v, we integrate cosx to get v=sinx Using the formula: The integral of x.dv/dx=uv-integral of v.du/dx So, to reiterate we have: u=x du/dx=1 v=cosx dv/dx=sinx So, using the formula, we need to find uv and the integral of v.du/dx 1) uv=x.sinx=xsinx 2) v.du/dx=sinx.1=sinx By using the formula as listed above: 1) xsinx-integral(sinx)= xsinx-(-cosx)+c= xsinx+cosx+c Therefore, the answer is xsinx+cosx+c

AF
Answered by Amelia F. Maths tutor

16397 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find dy/dx in terms of t for the curve defined by the parametric equations: x = (t-1)^3, y = 3t - 8/t^2, where t≠0


Mechanics 1: How do you calculate the magnitude of impulse exerted on a particle during a collision of two particles, given their masses and velocities.


A curve with equation y=f(x) passes through the point (1, 4/3). Given that f'(x) = x^3 + 2*x^0.5 + 8, find f(x).


Integrate tan (x) with respect to x.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences