Differentiate: y = 4x^3 - 5/x^2

To make this equation easier to differentiate it would be easier to write it using index rules as y = 4x^3 - 5x^-2 From here we can begin to differentiate: dy/dx = 3*4x^(3-1) - (-2)*5x^(-2-1) Then finally simplify the equation above to give: dy/dx = 12x^2 +10x^-3

CB

Related Maths A Level answers

All answers ▸

Differentiate y = x sin(x)


What is Bayes' rule and why is it useful?


f(x)= 2x^3 -7x^2 + 2x +3. Given that (x-3) is a factor of f(x), express f(x) in a fully factorised form.


Given that y = 4x^3 – 5/(x^2) , x =/= 0, find in its simplest form dy/dx.