Solve the differential equation dy/dx=(y^(1/2))*sin(x/2) to find y in terms of x.

Here, we must first rearrange our equation so all x terms are on one side and all y terms are on the other. Multiplying both sides by dx and diving both by y^(1/2) gives us y^(-1/2)dy = sin(x/2)dx, which is a directly integrable equation. Integrating both sides, we get 2y^(1/2) = -2cos(x/2) + c, where c is some arbitrary constant of integration. Rearranging to find y, we get y=(-2cos(x/2) + A)^2, where A=c/2.

Answered by Alex J. Maths tutor

6319 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How to differentiate e^x . sin(x)


Express '6cos(2x) +sin(x)' in terms of sin(x).


The curve C is defined by x^3 – (4x^2 )y = 2y^3 – 3x – 2. Find the value of dy/dx at the point (3, 1).


Work out the equation of the normal to the curve y = x^3 + 2x^2 - 5 at the point where x = -2. [5 marks]


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences