Differentiate y = (x^2 + 3)^2

We have to use the chain rule here. If we set u to the inside of the bracket, u = x^2 + 3 and differentiating we get du/dx = 2x. Now the original expression becomes y = u^2. Differentiating this with respect to x, dy/dx = du/dx * dy/du using the chain rule. dy/du = 2u and du/dx is 2x so the final answer dy/dx = 2x*2(x^2 + 3) = 4x(x^2 + 3).

Answered by Matthew H. Maths tutor

6442 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the integral of ln x


A curve is given by the equation y = (1/3)x^3 -4x^2 +12x -19. Find the co-ordinates of any stationary points and determine whether they are maximum or minimun points.


ln(2x^2 + 9x – 5) = 1 + ln(x^2 + 2x – 15). Express x in terms of e


Differentiate y=x/sin(x)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences