find the coordinate of the maximum value of the function f(x) = 9 – (x – 2)^2
Firstly you would start by differentiating the function and equating it to zero as the gradient of the function at the maximum point is zero. to differentiate this function you would use the chain rule since it is in the form f(x)=h(g(x)). -2(x-2) = 0 then you can see that the only solutions to this equation is when x = 2 so you plug that back into the equation to get : y = 9 - (2-2)^2 = 9 so coordinate is (2,9).
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