How would I find the approximate area enclosed by the expression e^x*sin(x)*x^3 on an infinite scale?

The area under a curve is analytically calculated using the integral of the function. The integral of the function above could be calculated using integration by parts twice, considering that 3 functions are multiplied together, this could messy and a bit tricky. To work out an approximate area the shapes of the individual graphs of e^x, sin(x) and x^3 can be considered individually.

Sin(x) oscillates between 1 and -1 continuously, meaning that the area under the curve above and below the x axis will be approximately equal and opposite (positive for above the x axis and negative for below) on an infinite x axis resulting in the area under the curve being approximately zero.

The same goes for the graph of x^3. Where x is positive so are the y coordinates, where x is negative the y coordinates follow suit, meaning that the areas above and below the x axis will be approximately equal again, cancelling one another out.

Therefore, the only integral that actually needs to be considered is the area under y=e^x, which is y=e^x.

Answered by Matthew W. Maths tutor

2742 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Proof by Induction - "What's the point if we already know the answer?"


Prove: (1-cos(2A))/sin(2A) = tan(A)


Why do you not add the 'plus c' when finding the area under a graph using integration even though you add it when normally integrating?


Given that 2cos(x+50)°=sin(x+40)° show tan x° = tan 40°/3


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences