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(2x+3) (2x+1) = 4x^2 + 8x + 3

(2x-8) (x-4) = 2x^2 - 16x - 32

(4x^2+8x+3) - (2x^2-16x-32) = 1

2x^2 - 8x - 29 = 1

2x^2 - 8x - 30 = 0

x^2 - 4x - 15 = 0

Using the qua...

Using factorisation, first we would have to look at the factors that multiply to make the last term, (-14). We know that they are +/- 7 and -/+2, and +/- 14 and -/+ 1, respectively. Now we have listed the...

Equation: a+3 = (2a+7)/r

First, we want to rearrange the equation, so that the 'r', which is the denominator of the right hand side, multiplies with (a+3), creating r(a+3) = 2a+7. ...

If for example you have g square x g cube, all you have to do is add up the potencies and put them in the same base, so in this case it will be g⁵. in the case of dividing potencies all you hav...

7x = 3x + 24 4x = 24 x = ²⁴/₄ x = 6