Firstly, you must factorise the quadratic equation on the numerator of the fraction. Observe that the x^2 has a coefficient of 2 and the term with no x terms is 3. 3 can only be factorised by 1 and 3. Also, notice that all signs are positive. Therefore we can set up two possibilities and by power of deduction, factorise the equation:

(2x + 1) (x + 3) = 2x² + x + 6x + 3 = 2x² + 7x + 3
(2x + 3) (x + 1) = 2x² + 3x + 2x + 3 = 2x²+ 5x + 3

Number 2 is the correct expansion

So we have the following expression where we can cancel out the (x + 1) terms to get:

(2x + 3)~~(x + 1)~~ / (~~x + 1)~~

= 2x + 3

Find the roots of x^2+5x+4=0

Related Maths GCSE answers

Factorise and simplify the following equation: (2x^2 + 5x + 3) / (x + 1)

The equation of line A is y = 6x -4. The equation of line B is 2y - 12x + 14 = 0. Are these two lines parallel?

Why do the denominators have to be equal when adding fractions, but not when multiplying them?

Expand (x+2)^2

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