Expand completely: (3a-6)(a+3)

Final Answer: a2 +3a -18 Using FOIL (First, outside, inside, last) we multiply the terms in the brackets together. First: 3a multiplied by a = 3a Outside: 3a x 3 = 9a Inside: -6 x a= -6a Last: -6 x 3 = -18 Combine these terms to get your final answer: 3a2+9a-6a-18= 3a2+3a-18

SS

Related Maths GCSE answers

All answers ▸

Solve the following simultaneous equations: 6j+4k=40; 7j-3k=-7


How do I complete the square


Expand (x-3)(x+7)


Solving quadratic equations using the factorisation method.