Make x the subject of the formula: 3(2x-y)=ax-4

Expand the brackets out first6x-3y=ax-4Now, get all the x's on one side6x-ax=3y-4and now factorise the side with the x's as we want to isolate xx(6-a)=3y-4and now divide both sides by (6-a)x=(3y-4)/(6-a)

Answered by Charul R. Maths tutor

2983 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find the roots of the equation (x^2+5x+4)/(x^2-3x+2)


3/5 of a number is 162. what is the number?


Show algebraically that (4n-3)^2 - (2n+5)^2 is always a multiple of n-4


A linear sequence starts a + 2b, a +6b, a + 10b. The 2nd has a value of 8 and the 5th term has a value of 44. What are the values of a and b?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences