root3 (root6 + root12) can be written as Aroot2 + B

root3 (root6 + root12) (root3 * root6 ) + (root3 +root12) = root18 + root36= (root9 + root2) + 6= 3root2 +6a= 3 b = 6

Answered by Dorcus M. Maths tutor

2767 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Show me why the product of a squared and a cubed is a to the power of 5.


Expand the quadratic equation and simplify: (3a+4)(a-1)


Solve the simultaneous equations: 3x-y=13, 2x+y=12


f(x) = (x+1)^2 and g(x) = 2(x-1); Show that gf(x) =2x(x+2)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences