Solve the equation to 2 two decimal places: (2x+3/x-4 ) - (2x-8/2x+1) = 1

 (2x+3/x-4 ) - (2x-8/2x+1) = 1 (2x+3/x-4) = 1 + (2x-8/2x+1) [Add (2x-8/2x+1) to each side]2x+3= x-4 + (2x-8)(x-4)/2x+1 Times both sides by (x-4)(2x-1)=(x-4)(2x+1) + (2x-8)(x-4) [Times both sides by (2x+1) - therefore we have removed the denominators from both sides]
Expand all to give;4x2 + 8x + 3= 2x2 - 7x -4 + 2x2 - 16x - 32 [Collect like terms, and simplify]-25 = -31x0.81 = x [Divide to give x, and round to two decimal places as asked]

JK
Answered by Jude K. Maths tutor

3292 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A right angled triangle has two smaller sides length 3 and 4, what is the length of its longest side?


Sketch a graph of the equation of y=3x+2


Solve the simultaneous equations x^2+y^2=1 and x+2y=1


Given 4x+7y=25 and 2x+5y=17, identify x and y by solving the simultaneous equations


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences