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The -OH is an activating group, it donates its lone pair into the delocalised ring of electrons. This increases the electron density in the ring, making it more reactive.
Ka = [H+][B-]/[HB]Benzoic acid dissociates to C6H6COO- and H+ - this is a 1:1 ratio so the concentrations are equal hence [H+][B-] = [HAnswered by Michael B. • Chemistry tutor20188 Views
Using "Le Chatelier's principle", the equilbrium will seek to oppose the change made to the reaction. In order to counter the increase in oxygen concentration, the reaction will shift to...
A proton ( H+ ion) donor
1s2 2s2 2p5
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