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This qustion can be solved easily using the gradient formular, m = ∆y/∆x, and some simple algrebra.
The gradient at the point x = 2 is calculated by find the gradient of a tangent at x = 2. To find...
We can expand following any row or column we want. A wise choice would be to use a row/column in which we have one or more zero entries to reduce the calculations. From this, we pick the first entry on th...
Let P(n) be the statement “(n^3)-n is divisible by 3”
First we’ll examine the base case: P(1)
(n^3)-n=1^3-1=1-1=0
0=3*0, so is divisible by 3, and so P(1) is true
Now assume fo...
Often in Further Pure modules for various exam boards a common question in the exam paper will be to sketch a graph for a rational function. The step by step aproach I used is as follows:
We first want to get every term in terms of the same variable, namely sin(x). to do so, we will use the identity sin^2(x) +cos^2(x) = 1 to get: 4(1-sin^2(x)) -15sin(x) -13 = 0. which we can then rewrite a...
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