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Further Mathematics
A Level

How can we describe complex numbers ?

The simplest way to describe a complex number is by its real and imaginary part, z=x+yi, this may be wrote as Re(z)=x and Im(z)=y. These complex numbers follow the same r...

Answered by Thomas L. Further Mathematics tutor
2289 Views

Evaluate ∫sin⁴(x) dx by expressing sin⁴(x) in terms of multiple angles

First we remember that sinθ can be expressed in terms of powers of z, where z=cos(θ)+isin(θ), using the following:2isin(nθ)=zⁿ-z⁻ⁿ and 2cos(nθ)=zⁿ+z⁻ⁿ
so, [2isin(θ)]⁴=[z¹-z⁻¹]⁴ 16sin(θ)=(z)⁴(-z⁻¹)⁰+4...

Answered by Nicholas H. Further Mathematics tutor
3009 Views

Prove by mathematical induction that 2^(2n-1) + 3^(2n-1) is divisible by 5 for all natural numbers n.

First check that this works for n=1:2^(2x1 - 1) + 3^(2x1 - 1) = 2^1 +3^1 = 5 (so true for n=1)Now we assume this to work for any n = k.Assumption: 2^(2k-1) + 3^(2k-1) = 5a, where a is some integer constan...

Answered by Kristina I. Further Mathematics tutor
10321 Views

How can the integrating factor method be derived to give a solution to a differential equation?

Consider the general equationdy/dx + Py = Qwhere P and Q are functions of x.R (which will be introduced later) is also a function of x.
So, all of a sudden, we are going to just state the product rul...

Answered by Jack H. Further Mathematics tutor
1885 Views

Prove by induction the sum of n consecutive positive integers is of the form n(n+1)/2.

As proof by induction goes we always have to show that it works for the base case, which in this case is the very first positive integer:1. So we show that the sum of the first number(s) is equal to one w...

Answered by Patryk S. Further Mathematics tutor
6629 Views

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