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We’re being asked to differentiate the function with respect to x. To do so, we use the general formula for differentiation, which is:‘If y = kxn, dy/dx = nkx(n-1)We must also note that, ...
f'(x)=3cos3x-3differentiating the sin3xchain ruley =sinu u=3xdy/du=cosu du/dx=3dy/du x du/dx = 3cosuu= 3x3cos3x - 3
Quotient Rule:d(u/v)/dx = (vu' - uv')/(v2)u = sin(2x) => u' = 2cos(2x)v = x2 => v' = 2x=> (2x2cos(2x) - 2xsin(2x))/(x4)Product Rule:d(uv)/dx = vu' + uv...
We can rewrite the function to eliminate the annoying 1/x^2 expression by knowing this can also be expressed by x^-2.f(x) = 6x^-2 + 2xNow we can differentiate this function term by term, first 6x^-2. We k...
This is a common A-level question tackling functions and differentiation. (a) First, it should be noted that the function f is defined within the field of real numbers and thus the value of 2x-2 in the sq...
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