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express (1+4(root7)) / (5+2(root7)) as a+b(root7), where a and b are integers

1+4(root7) x 5 - 2(root7)5+2(root7) 5 - 2(root7)5 - 2(root7) + 20(root7) - (8x7) 25 - (4x7)5 +18(root7) - 56 -3-51 + 18(root7) -317 - 6(root7)ie a = 17, b = -6

Answered by Hannah B. • Maths tutor

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A curve has equation y = 20x −x2 −2x3 . (A) Find the x-coordinates of the stationary points of the curve.

Firstly, differentiate the equation to find dy/dx.
dy/dx = 20 - 2x - 6x²
As dy/dx represents the gradient, we know that for a stationary point the gradient must be zero, hence for the...

Answered by Bradley W. • Maths tutor

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f(x) is defined by f(x) = 3x^3 + 2x^2 - 7*x + 2. Find f(1).

f(1) = 31^3 + 21^2 - 7*1 + 2 = 3 + 2 - 7 + 2 = 0

Answered by Dragos M. • Maths tutor

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A curve has equation y = 20x - x^2 - 2x^3 . The curve has a stationary point at the point M where x = −2. Find the x- coordinate of the other stationary point of the curve

A stationary point on a curve is when the differential of the equation of the curve = 0. In other words when dy/dx = 0Take the equation in the question: y = 20x - x² - 2x³A simple ru...

Answered by Henry J. • Maths tutor

3385 Views

Find the equation of the line through the following points: (-2, -3) and (1, 5)

Note the formula: y - y₁ = m(x - x₁)x, y, x_1,y₁ refer to the values of your given coordinates. 'm' symbolises the gradient of the line you are asked to findRe...

Answered by Tise O. • Maths tutor

2861 Views