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Find the stationary point of the graph of y = 2x + 5 + 27x^(-2)

y = 2x + 5 + 27x^-2To find a stationary point, find the gradient function by differentiating with respect to x:y' = 2 -54x^-3To find a stationary point, let the gradient function equal...

Answered by Henry H. • Maths tutor

3301 Views

Find the co ordinates and nature of the turning points of the curve C withe equation, y=2x^3-5x^2-4x+2

Firstly, Differentiate the equation to find dy/dx. (dy/dx = 6x^2-10x-4)dy/dx shows the rate of change of the curve at a point, so at the stationary point dy/dx =0. So, put dy/dx = 0 and solve using factor...

Answered by Asha K. • Maths tutor

8473 Views

Locate the position and the nature of any turning points in the function: 2x^3 - 9x^2 +12x

I would first ask the student to draw a cubic graph(preferably the function in asking depending on the student's capability). I would then ask the student to show me where the stationary points in the gra...

Answered by Ewa I. • Maths tutor

5581 Views

Simplify 3log(x^2)+4log(y^3)

Using rules of logarithms: 3log(x^2)+4log(y^3)=log((x^2)^3)+log((y^3)^4) =log(x^6)+log(y^12) =log((x^6)(y^12)

Answered by Alexander C. • Maths tutor

3726 Views

How do I find the equation of the normal to the curve y=x^2 at the point (x1,y1)? Where x1=2 and y1=4 .

I would get the student to draw a diagram of the situation.. so draw the curve y=x^2, the tangent at (2,4) and then the normal. Then I would highlight to them that the equation we want is the equation of ...

Answered by Mohammad M. • Maths tutor

3782 Views