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To find the area enclosed by a function, we need to use integration. Here, the function is not easy to integrate just by inspection, but it is the product of two functions we do know how to integrate: cos...
explain the following briefly: To work out the gradient, first principles, shortcutsexplain in detail: different methods
y = 3x2 + 6x1/3 + (2x3/3 - 7/3)x-1/2Using the multiplication rule for indices y = 3x2 + 6x1/3 + (2/3)x5/2 - (7/3)x-1/2Answered by • Maths tutor5660 Views
you would first change the equaton into the circle equation therefore completing the square (x -2)^2 -4 + (y + 5)^2 -25 = know use the equation to deduce the center of the circle (x -2)^2 + (y + 5)^2 = ...
dy/dx = 2x -2 - 12x^-0.5d^2/dx^2 = 2 + 6 x^-3/2
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