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Maths
A Level

Differentiate the following equation: y = 2(x^3) - 6x

Firstly we look at the term 2(x^3). The power of x (in this case 3) is multiplied by the factor of x (in this case 2) and the power is then reduced by 1. This means it is 2x3(x^{3-1}) which simplifies to ...

Answered by Anna W. Maths tutor
3120 Views

y = 3x^2 + 2x^(1/2) - 12 Find dy/dx

Firstly we divide up the equations into its three compenents based on the powers of the x values, giving us 3x^2, 2x^(1/2) and -12. Now one at a time, we multiply the coefficient by the power of x, and th...

Answered by Sam R. Maths tutor
5197 Views

Solving 2tan(x) - 3sin(x) = 0 for -pi ≤ x < pi

The first step to answering this question is to get the equation in a simpler form. Aim to have it solely in terms of sin(x) and cos(x) with no fractional parts.                                           ...

Answered by Benjamin A. Maths tutor
19559 Views

Take the polynomial p(x)=x^4+x^3+2x^2+4x-8, use the factor theorem to write p(x) as two linear factors and an irreducible quadratic. An irreducible quadratic is a quadratic that can not be factorised.

We must use the factor theorem since that is what the question asks. So we take p(x) and think about the factors of 8 we then evaluate it at x=1 to start, then move onto x=-1,2,-2 and so on. We see that i...

Answered by Jordan C. Maths tutor
3404 Views

How would the integral ∫x^2sin2xdx be solved using integration by parts?

The general formula for integration by parts is given as
∫u(dv/dx)dx = uv - ∫v(du/dx)dx
given that the equation to be solved is ∫x2sin2xdx, the values for u, v, du/dx and dv/dx can ...

Answered by Samuel N. Maths tutor
9805 Views

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