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A. t=0 ; x=250,000 B. 2020, so t=3. plug in to equation > x=250,000e^(0.012)3 = 259,163 (people so cannot round up) C. Population to double so 500,000 = 250,000e^(0.012)t -> 1/0.012(ln2) = t t= 57.7...

step 1 remember than the a and b terms locate the centre of the circle on the axis so we can substitute in the centre values for a and b. (x-5)^2 + (y-(-3))^2 = k. (x-5)^2 + (y+3)^2 = k.

Step 2. k ...

(i): 15x^(2)+7 --- in order to arrive at this answer, we can divide the equation into 3 separate parts: 5x^(3) and 7x and 3. For the first part, you would multiply the first number, 5 by the power, in thi...

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By differentiating with respect to x, 3x^2+6x(dy/dx)+6y+2y(dy/dx)=0 So, dy/dx(6x+2y)=-3x^2-6y so dy/dx = -(3x^2+6y)/(2(3x+y))