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Maths
A Level

How do you find the gradient of a line at a certain point when f(x) is in the form of a fraction, where both the numerator and denominator are functions of x?

Take the example f(x)=(2x^2+1)/(3x+5) , where we're finding the gradient at x=0. First, you need to differentiate f(x) to get f'(x). Because f(x) is a fraction where both the numerator and denominator are...

PE
Answered by Phoebe E. Maths tutor
5903 Views

How do you find the turning points of a graph and how do you if the point is a maximum or a minimum?

Firstly you have to find the turning points of the graph. This is done by differentiating the equation of the line. Once you have found this first derivative, equate the equation to zero. Now solve the eq...

HH
Answered by Harry H. Maths tutor
21325 Views

Integrate (x)(e^x) with respect to x and then integrate (x)(e^x) with respect to y.

i) By integration by parts, we see that it equals (x)(e^x)-(e^x)+C, where C denotes the constant of integration. ii) (x)(y)(e^x)+C, where C denotes the constant of integration.

RV
Answered by Rohan V. Maths tutor
4081 Views

How do you find the possible values of cos(x) from 5cos^2(x) - cos(x) = sin^2(x)?

First, you start by replacing sin^2(x) with 1-cos^2(x) as you want the equation to be in terms of cos(x) and you know sin^2(x)+cos^2(x) = 1. Then you rearrange the equation to get 0 on one side so that yo...

GK
Answered by Gowri K. Maths tutor
4044 Views

By completing the square, find the values of x that satisfy x^4 -8x^2 +15 = 0

x^4 -8x^2 +15 = 0, we rewrite the equation in square form as (x^2-4)^2 -16 +15 =0 (x^2 -4)^2 = 1 x^2 -4 = ±1 so x^2 = 4±1, (x^2 = 3 or x^2 = 5) Therefore x = {-√3, √3, -√5, √5)

CS
Answered by Callum S. Maths tutor
2839 Views

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