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cos(x) + (1/2)sin(x) :
Rsin(x + a) = R{sin(x)cos(a) + cos(x)sin(a)} = (1/2)sin(x) + (1)cos(x) (comparing coeffs.)
Therefore Rcos(a) = 1/2 and separately Rsin(a) = 1 So tan(a) = 2 and R^2 =...
A general way of solving these equations is getting them to the form sin(y)=k. In this case, to do so, we have to divide by 2 and then put y=3x+45° We then get si...
A general method would be to compute a and b with the general solution formula for quadratic equations. However, a special property of quadratic equations can make this a...
Here it is necessary to use the chain rule to solve the derivative. If we equate our equation in terms of the following notation: ln(x)='u'and 2x^2='v' and use the chain rule formula dy/dx=udv/dx+vdu/dx w...
sin2x = 2sinxcosx cos2x = cos^2(x) - sin^2(x) tan2x = (2tanx)/(1-tan^2(x))
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