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The key is to look at the first and second derivatives of that function. Remember that a turning point always has the first derivative equal to zero. Then, the sign of the second derivative indicates if t...
Starting with x=2cosu, rearrange for u to get u=arccos(x/2), then find the upper and lower limits of the integral. We find that our lower limit goes from 1 to pi/3, ad our upper limit goes from root 2 to ...
1/2 *e^(x)(sin x -cos x)
y=5x2-2x+3 Differentiate to find the equation of the gradient of the curvedy/dx=10x-2 Substitute x=0 to find the gradient at the point x=0dy/dx=-2y=50^2-2Answered by • Maths tutor4776 Views
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