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How to differentiate y=2x(x-2)^5 to find dy/dx?

Firstly, you should formulate the problem by using the product rule, which is: dy/dx = u'v + v'uBy assigning u=2x and v=(x-2)

Answered by Anup P. • Maths tutor

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If h(x) = 2xsin(2x), find h'(x).

Differentiate using product rule as expression consist of two functions.Product Rule: d(f(x)g(x))/dx = g(x).f'(x) + f(x).g'(x)Chain Rule: d(f(g(x)))/dx = g'(x) . f'(g(x))
Let: f(x) = 2x f'(x) = 2 - s...

Answered by Meer S. • Maths tutor

3312 Views

Differentiate the following: y = 3x^(1/3) + 2

Answer: dy/dx = x^-2/3Explanation: When differentiating, we bring the power to the front and subtract 1 from the power to get the new power. So the first term becomes (3 x 1/3)x^{(1/3 - 1)}

Answered by Scarlett S. • Maths tutor

2498 Views

Find the intergral of 2x^5 - 1/4x^3 - 5 with respect to x.

2x⁵ - 1/4x³ - 5 can be intergrated by intergrating each term seperately and then remembering to add a constant to your new answer. Therefore the correct answer would be x⁶...

Answered by George H. • Maths tutor

2892 Views