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The part of syllabus covered by this question is proof by contradiction. Consequently, in order to achieve a contradiction, you can assume that root2 is rational and thus expressed as a/b where a and b ar...
Given a ODE of the 2nd order, Ay''+by'+cy = 0, we assume the general solution of the exponential form y=e^(mx).As we will see this leads to an easy simplification due to the properties of the exponential ...
This is done using the integration by parts method.Answer: (e^x)((x^2) - (2x) - 2) + c
f(x) = 6x2+2x+1, f'(x)= [f(x+h)-f(x)]/h here is the original equation and the formula used to differentiate from first principles. For this proof the limit of h is: h=0 and should be stated thr...
For differentiation, we can follow a simple method for differentiating y with respect to x. It may be the case that you have special numbers such as ex you need to differentiate and integrate b...
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