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Maths
A Level

The curve C has the equation y=((x^2+4)(x-3))/2*x where x is not equal to 0 . Find the tangent to the curve C at the point where x=-1 in the form y=mx+c

Firstly we need to expand out y into a series of terms to make it easier for us to compute the derivative . You multiply out the brackets to get y=(x3-3x2+4x-12)/2x then we divide ea...

Answered by Ellie M. Maths tutor
11109 Views

Let z=x+yi such that 16=5z - 3z*, What is z?

z* is the complex conjugate of z therefore z* = x - yi. So 16 + 32i = 5(x + yi)-3(x - yi), real: 16 = 5x - 3x => 16=2x => x=8, imaginary: 32 = 5y + 3y => 32 = 8y => y=4, therefore z = 8 + 4i.<...

Answered by Ben C. Maths tutor
2784 Views

f(x)=12x^2e^2x - 14, find the x-coordinates of the turning points.

f(x)=(12x^2)(e^2x) - 14, so using the chain rule f'(x)=(24x)(e^2x) + (12x^2)(2e^2x).To find the turning points set f'(x)=0, so (24x)(e^2x) + (24x^2)(e^2x) = 0. Thus (24xe^2x)(1+x)=0. Thus x=0 or x=-1.

Answered by Charlotte H. Maths tutor
2761 Views

Rationalise the surd: 2/root(x)

To rationalise a surd means to manipulate a fraction involving terms which are being square rooted so that no term in the denominator is being square rooted. For this example 2/root(x) we multiply the fra...

Answered by Daniel T. Maths tutor
8185 Views

(a) Express x +4x+7 in the form (x+ p) +q , where p and q are integers.

(x + 2)2+3

Answered by Dylan S. Maths tutor
3676 Views

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