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Firstly we need to find the stationary point on the curve. We know what at a stationary point the gradient is zero so we will find the gradient of the curve. We do this by differentiation, when we have di...

Integration by parts should be used when you want to integrate a function composed of two factors (we can call them 'u' and 'dv'), where it is fairly easy to derive 'u', while it is difficult or impossibl...

Firstly we rearrange the expression to the required form:x² + y² + 20x - 14y + 49 = 0 which gives (x + 10)² - 100 + (y - 7)² - 49 + 49 = 0 and so ...

Firstly split up the ln(x/7) = ln(x) - ln(7) using rules of logarithms learnt in your first year of A-levels, as this will reduce any likely error.Secondly, recognise that the -ln(7) term is constant, and...

h dy/dx (4) = 0.03y(4.3) = 8+0.03 = 8.03y(4.6) = y(4.3) + 0.3 dy/dx(4.3) = 8.0581 to 4 d.p