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Maths
A Level

The curve C has equation: 2x^2y + 2x + 4y – cos (piy) = 17. Use implicit differentiation to find dy/dx in terms of x and y.

You want to take the derivative of both sides of the equation with respect to x which produces an equation in terms of x, y and dy/dx which can then be rearanged. The right side is just 0 since 17 is a co...

Answered by Maths tutor
4311 Views

find dy/dx= x^2 +x^3

dy/dx= 2x+(1/3)x^2

SA
Answered by Safa A. Maths tutor
2895 Views

Using the parametric equations x=6*4^t-2 and y=3*(4^(-t))-2, Find the Cartesian equation of the curve in the form xy+ax+by=c

Firstly make t the subject for both equations
(x-7)/6=4^t
(y+2)/3=4^(-t)
Times them together to eliminate t
((x-7)/6)((y+2)/3) = (4^t)*(4^-t)=4^0=1
Rearrange to the form required<...

AC
Answered by Anya C. Maths tutor
2806 Views

f(x)= 2x^3 -7x^2 + 2x +3. Given that (x-3) is a factor of f(x), express f(x) in a fully factorised form.

We will mainly be using a whiteboard but here are some notes:Is (x-3) is a factor of f(x), then if x=3, f(x) =0. I.e. x=3 is a solution too. If we know x =3 is a solution we can solve the other 2 roots by...

RR
Answered by Rumana R. Maths tutor
3932 Views

Given x=Sqrt(3)sin(2t) and y=4cos^2(t), where 0<t<pi. Show that dy/dx = kSqrt(3)tan(2t).

Differentiating the equation for x with respect to t, we get: dx/dt=2Sqrt(3)cos(2t);Take the reciprocal of dx/dt to get dt/dx=1/[2Sqrt(3)cos(2t)]Using a trigonometric identity on the equation for y, we ge...

PC
Answered by Peter C. Maths tutor
4378 Views

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