Search over 10,000 free study notes

Find out what they know what the questions means, ie if they know what sinx and cosx are and then how much they understand about what derivatives are.I would explain from the point they're at, define ever...

(a) To find the second derivative of f(x) we must differentiate f twice.the first derivative of f is f'(x)= 3x^2 + 6xthe second derivative therefore is f''(x)= 6x +6
(b) The integral of f(x) with res...

2^2x - 6(2^x ) + 5 = 0let y = 2^xy² - 6y + 5 = 0(y-5)(y-1) = 0 y=5, y=12^x = 5, therefore, x = log₂5 = 2.32 (3 s.f.)2^x = 1, therefo...

Firstly, establish that the correct method to do this is via differentiation: specifically implicit differentiation. To find the gradient, we need to find dy/dx. The differential with res...

As f(x) is in the form of u(x)/v(x) we can apply the rule that f'(x) = (u'(x)*v(x) - v'(x)*u(x))/(v(x)²), pulled from the C3 formula booklet.
If u(x) = sin(2x) then u'(x) = 2cos(2x).
...